已知2(a-2)^2+(b+1)^2=0,求代数式3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+1/2a^2b的值
彭洁回答:
2(a-2)^2+(b+1)^2=0,
a-2=0a=2
b+1=0b=-1
3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+1/2a^2b
=1/2a^2b+2ab^2+ab
=1/2x4x-1+2x2x1+2x-1
=-2+4-2
=0
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已知2(a-2)^2+(b+1)^2=0,求代数式3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+1/2a^2b的值
彭洁回答:
2(a-2)^2+(b+1)^2=0,
a-2=0a=2
b+1=0b=-1
3a^2b+ab^2-3a^2b+5ab+ab^2-4ab+1/2a^2b
=1/2a^2b+2ab^2+ab
=1/2x4x-1+2x2x1+2x-1
=-2+4-2
=0