ab+a+b=cbc+b+c=aac+a+c=b解方程组……
史金松回答:
两边同时加1得(a+1)(b+1)=c+1,同理(b+1)(c+1)=a+1,(c+1)(a+1)=b+1,三式相乘得[(a+1)(b+1)(c+1)]^2=(a+1)(b+1)(c+1),所以,(a+1)(b+1)(c+1)=0或1,当(a+1)(b+1)(c+1)=0时,代入可得a+1=b+1=c+1=0,则a=b=...
蒋冰回答:
两边怎么加1?
史金松回答:
ab+a+b=cab+a+b+1=c+1(a+1)(b+1)=c+1
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